Problema Solution
A junior high school student is deciding between two jobs:
Job 1: Babysitting for $80 per month.
Job 2: Delivering papers for 18ยข per paper.
What is the fewest number of papers she would need to deliver per month to exceed the babysitting salary ?
Answer provided by our tutors
Let
x = hours babysitting and x > 1
y = number of papers delivered
0.18*y > 80*x
y > (40/0.09)*x > 40/0.09 > 444
The first natural number bigger then 444 is 445 therefore 445 is the fewest number of papers she needs to deliver.