Problema Solution
four times a first number decreased by a second number is 8. The first number increased by twice the second number is 20. Find the numbers
Answer provided by our tutors
let
x = the first number
y = the second number
four times a first number decreased by a second number is 8
4x - y = 8
first number increased by twice the second number is 20
x + 2y = 30
by solving the system of equations
4x - y = 8
x + 2y = 30
we find that
x = 46/9
y = 112/9
the numbers are 46/9 and 112/9.