Problema Solution

four times a first number decreased by a second number is 8. The first number increased by twice the second number is 20. Find the numbers

Answer provided by our tutors

let


x = the first number

y = the second number


four times a first number decreased by a second number is 8


4x - y = 8


first number increased by twice the second number is 20


x + 2y = 30


by solving the system of equations


4x - y = 8

x + 2y = 30


we find that


x = 46/9


y = 112/9


the numbers are 46/9 and 112/9.