Problema Solution
suppose that the width of a rectangle 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=2L+2W.
a)set up an equation for the perimeter involving only L, the length of the triangle.
b) solve this linear equation algebraically to find the length of the rectangle. find the width as well.
c) using the same width as your answer from part b), find a new perimeter if the new length is 4 less than three times the width.
Answer provided by our tutors
suppose that the width of a rectangle 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=2L+2W.
a)set up an equation for the perimeter involving only L, the length of the triangle.
W=L-5.
P=2L+2(L-5).
=2L+2L-10.
=4L-10.
b) solve this linear equation algebraically to find the length of the rectangle. find the width as well.
4L-10 =50.
4L=60.
L=60/5
=15 inches.
W=L-5 =15-5
W=10 inches.
c) using the same width as your answer from part b), find a new perimeter if the new length is 4 less than three times the width.
L=3W-4.
L=3*10-4.
=26.
Perimeter P=2L+2W.
=2*26+2*10
=72 inches.