Problema Solution
The length of a rectangle is 3ft less than twice the width, and the area of the rectangle is 44ft^2. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
A = w*l is the are of the rectangle and A = 44 ft^2
the length of a rectangle is 3ft less than twice the width
l = 2w - 3
the area of the rectangle is 44ft^2
l*w = 44
by replacing l = 2w - 3 in the above equation we have
(2w - 3)w = 44
solving the quadratic equation we find and consider only the positive roots since w>0
w = 5.5 ft
l = 2*5.5 - 3
l = 8 ft
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the dimensions of the rectangle are 8 ft and 5.5 ft.