Problema Solution
Find three consecutive numbers such that eight times the third plus twice the first is equal to six times the second. find the numbers.
Answer provided by our tutors
let the 3 consecutive integer numbers be
x - 1, x, x + 1
where x is integer
8 times the third plus twice the first is equal to 6 times the second
8(x+1) + 2(x - 1) = 6x
by solving the equation we find
x = -1.5
and since x must be an integer follows that there are no such numbers
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