Problema Solution
The position of an object moving in a straight line is given by the function s(t)= 2t-3t, where s(t) represents distance traveled and t represents the time the object has been in motion. How long (to the nearest tenth)will it take the object to move 17 meters?
Answer provided by our tutors
We will consider this question for the function s(t)= 2t^2-3t (instead s(t)= 2t-3t as typed in the question)
we must find t such that s(t) = 17 meters that is
2t^2-3t = 17
by solving the quadratic equation we find
t = 3.8 to the nearest tenth
click here to see the step by step solution of the quadratic equation
it takes 3.8 for the object to move 17 meters.