Problema Solution

a gym offers a variety of weights for use by its members. If there are 6 more 50-pound weights than 100-pound weights and 2 less than 6 times as many 20-pound weights as 100-pound weights, for a total of 2150 pounds, how many of each weight are there?

Answer provided by our tutors

let


x = the number of 20-pound weights

y = the number of 50-pound weights

z = the number of 100-pound weights


there are 6 more 50-pound weights than 100-pound weights


y = 6 + z


2 less than 6 times as many 20-pound weights as 100-pound weights,


x = 6z - 2


for a total of 2150 pounds


20x + 50y + 100z = 2150


by solving the system of equations


y = 6 + z

x = 6z - 2

20x + 50y + 100z = 2150


we find


x = 40 weights of 20-pounds


y = 13 weights of 50-pounds


z = 7 weights of of 100-pounds


click here to see the step by step solution of the system of equations


Click to see all the steps