Problema Solution
quadratic equations and systems of quadratic equations.
The iron counterweight is to have its weight increased by 50% by plates of iron bolted along the top and side (but not at the ends). The top plate and the side plate have the same thickness. Find their thickness.
The counter weight had original height of 22cm and the width of 28cm before, the new plates have been added
Answer provided by our tutors
The thickness: x in
So the added cross-sectional area / the origin area = 0.50
the added cross-sectional area = 22x +28x + x^2
the origin area = 22*28
So the equation is
22x +28x + x^2 = 0.50*22*28
x = 5.55 in
So
the thickness is 5.55 inches