Problema Solution
I have 30 coins, all nickels, dimes ,and quarters, worth $4.60
There are two more dimes than quarters.
How many of each coin do I have.
Answer provided by our tutors
1 nickel = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
let
n = the number of nickles
d = the number of dimes
q = the number of quarters
I have 30 coins, all nickels, dimes ,and quarters, worth $4.60 = 460 cents
n + d + q = 30
5n + 10d + 25q = 460
There are two more dimes than quarters
d = q + 2
by solving the system of equations
n + d + q = 30
5n + 10d + 25q = 460
d = q + 2
we find
d = 14 dimes
n = 4 nickles
q = 12 quarters
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