Problema Solution

How long will it take for a ball dropped from the top of a 225- foot building to hit the ground? Round your answer to two decimal places?

Answer provided by our tutors

the equation for the height of the ball h depending on the time t is given by


h(t) = (-1/2)g*t^2 + v0*t + h0


where


g = 9.81 m/s^2 is a given constant (the acceleration due to gravity)

v0 = 0 m/s in the initial velocity

h0 = 225 ft = 225*0.3048 m the initial height


h(t) = (-1/2)g*t^2 + 225*0.3048


we need to find t and t>0 such that h(t) = 0 that is


(-1/2)g*t^2 + 225*0.3048 = 0


by solving we find and consider the positive roots


t = 3.74 sec


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it will take 3.74 seconds for the ball to hit the ground.