Problema Solution
1.) Find two consecutive odd integers such that twice the larger is 15 more than three times the smaller.
Answer provided by our tutors
every odd integer can be written as 2k + 1, where k is integer
the 2 consecutive odd integers can be written as:
2k - 1, 2k + 1, where k is integer
2k + 1 is the larger
2k - 1 is the smaler
twice the larger is 15 more than three times the smaller
2(2k + 1) = 15 + 3(2k - 1)
by solving the equation we find
k = -5
click here to see the step by step solution of the equation
2*(-5) - 1 = -11
2*(-5) + 1 = - 9
the two consecutive odd integers are -9 and -11.