Problema Solution
Two planes left an airport at noon. One flew east the other flew west at twice the speed. After 3 hours the planes were 2700 miles apart? How fast was each plane flying?
Answer provided by our tutors
let
the speed of the first plane be: v
the second plane is flying in opposite direction at twice the speed of the first: 2v
After 3 hours the planes were 2700 miles apart
speed = distance/time => distance = speed*time
v*3 + 2v*3 = 2700
by solving the equations we find
v = 300 mph
click here to see the step by step solution of the system of equations
2v = 2*300 = 600 mph
the speed of the first plane was 300 mph while the speed of the second was 600 mph.