Problema Solution
the length of the rectangle is 5 more than twice the width if the perimeter is 64 units find the dimension of the rectangle
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of the rectangle is 5 more than twice the width
l = 5 + 2w
the perimeter is 64 units
2(l + w) = 64 divide both sides by 2
l + w = 32
by solving the system of equations
l = 5 + 2w
l + w = 32
we find
l = 23 units
w = 9 units
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the dimensions of the rectangle are 23 units and 9 units.