Problema Solution
find the maximum or minimum value of the function f(x)=1.2x^2+5.8x+3.7
Answer provided by our tutors
the function y = ax^2 + bx + c
a<0 has is maximum equal to c - b^2/(4a)
a>0 has is minimum equal to c - b^2/(4a)
f(x)=1.2x^2+5.8x+3.7
a = 1.2, b = 5.8, c = 3.7
a>0 follows the function has minimum
f min = 3.7 - 5.8^2/(4*1.2)
f min = -3.31
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