Problema Solution
find the maximum or minimum value of the function f(x)=3.2x^2+6.2x-4.3
Answer provided by our tutors
the function y = ax^2 + bx + c
a<0 has is maximum equal to c - b^2/(4a)
a>0 has is minimum equal to c - b^2/(4a)
f(x)=3.2x^2+6.2x-4.3
a = 3.2, b = 6.2, c = -4.3
a>0 follows the function has minimum
f min = - 4.3 - 6.2^2/(4*3.2)
f min = - 7.3
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