Problema Solution

find the maximum or minimum value of the function f(x)=3.2x^2+6.2x-4.3

Answer provided by our tutors

the function y = ax^2 + bx + c


a<0 has is maximum equal to c - b^2/(4a)


a>0 has is minimum equal to c - b^2/(4a)


f(x)=3.2x^2+6.2x-4.3


a = 3.2, b = 6.2, c = -4.3


a>0 follows the function has minimum


f min = - 4.3 - 6.2^2/(4*3.2)


f min = - 7.3


click here to see the graph of the function


Click to see all the steps