Problema Solution
andrew can paint the house 4 times faster then bailey. the year andrew and bailey worked together they painted the house in 9 days. How many days would it take each other to paint the house?
Answer provided by our tutors
let
a = the days Andrew needs to paint the house alone
b = the days Bailey needs to paint the house alone
the rate of Andrew is: 1/a house per day
the rate of Bailey is: 1/b house per day
the together rate is: 1/9 houses per day
1/a + 1/b = 1/9
Andrew can paint the house 4 times faster then Bailey
b = 4a
plug b = 4a into 1/a + 1/b = 1/9
1/a + 1/(4a) = 1/9
by solving we find
a = 11.25 days
click here to see the step by step solution of the equation
b = 4*11.25
b = 45 days
Andrew needs 11.25 days to paint the house alone.
Bailey needs 45 days to paint the house alone.