Problema Solution
The distance that a free falling object falls is directly proportional to the square of the time it falls. If an object fell 90 ft in 4 seconds, how far will it have fallen by the end of 8 seconds?
Answer provided by our tutors
let
d = the distance the free falling object falls
t = the time of the fall
d = k*t^2, where k is constant
an object fell 90 ft in 4 second means d = 90 ft, t = 4 sec
90 = k*4^2
16k = 90 divide both sides by 16
k = 90/16
k = 5.625
now the formula is d = 5.625*t^2
for t = 8 sec we have
d = 5.625*8^2
d = 360 ft
by the end of the 8 seconds the object will fall 360 ft.