Problema Solution
The area of a rectangle is 629 cm. If the length of the rectangle is 3 more than twice its width, find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
A = 629 cm the area of the rectangle
the length of the rectangle is 3 more than twice its width
l = 3 + 2w
the formula for the area of the rectangle is A = l*w
l*w = 629
plug l = 3 + 2w into l*w = 629:
(3 + 2w)*w = 629
by solving we find
w = 17 cm
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l = 3 + 2*17
l = 37 cm
the dimensions of the rectangle are: the width is 17 cm and the length is 37 cm.