Problema Solution
P takes 3 hours more than Q to walk 30 km.but if P doubles his pace he is ahead of Q by 1/2 hours find their speed walking.
Answer provided by our tutors
let
d = 30 km the distance
t = the time that Q walks
t + 3 = the time that P walks
since speed = distance/time we have
v1 = d/(t + 3) is the speed of P
v2 = d/t is the speed of Q
if P doubles his pace he is ahead of Q by 1/2 hours
the new speed of P is: 2d/(t + 3) thus the time of the walk will be d/(2d/(t+3)) = (t+3)/2
(t+3)/2 = t - 1/2
by solving we find
t = 4 hr
click here to see the step by step solution of the equation
v1 = 30/(4 + 3)
v1 = 4.29 km/hr
v2 = 30/4
v2 = 7.5 km/hr
P's speed of walking is 4.29 km/hr.
Q's speed of walking is 7.5 km/hr.