Problema Solution
Two cars leave towns 320 kilometers apart at the same time and travel toward each other. One car's rate is 16 kilometers per hour less than the other's. If they meet in 2 hours, what is the rate of the slower car?
Answer provided by our tutors
let
v = the rate of the slower car
v + 16 = the rate of the faster car
d = 320 km is the distance between the cars
t = 2 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v + 16)*t = d
2v + (v + 16)2 = 320
by solving we find
v = 72 km/h
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the rate of the slower car is 72 km/h.