Problema Solution
Fourteen hours after a convict escapes from prison, a prison guard begins to pursue him. How far from the prison will they meet, if the prisoner travels at 8 mph on foot and the guard at 64 mph in a car?
Answer provided by our tutors
let
d = the distance from the prison that each passes (the distance from the prison where they meet)
t = the time of the travel of the guard
t + 14 = the time of the travel of the convict
v1 = 8 mph the speed of the convict
v2 = 64 mph the speed of the guard
since distance = speed * time we have
v1*(t + 14) = v2*t
8(t + 14) = 64t
by solving we find
t = 2 hr
click here to see the step by step solution of the system of equations
d = 64*2 = 128 mi
the distance is 128 miles.