Problema Solution
if the perimeter of a rectangle is 96 inches and the length is 4 inches longer than the width, what is the area?
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
P = 96 in the perimeter of the rectangle
A = ? the area of the rectangle
the perimeter of a rectangle is 96 inches
P=2(l + w)
2(l + w) = 96 divide both sides by 2
l + w = 48
the length is 4 inches longer than the width
l = 4 + w
by solving the system of equations
l + w = 48
l = 4 + w
we find
l = 26 in
w = 22 in
click here to see the step by step solution of the system of equations
A = l*w
A = 26*22
A = 572 in^2
the area of the rectangle is 572 square inches.