Problema Solution
Find two consecutive positive integers whose product is 5 more than the square of the smaller integer.
Answer provided by our tutors
the two consecutive positive integers can be written as:
x and x+1, where x is integer and x>0
x is the smaller integer since x < x+1
x(x + 1) = 5 + x^2
by solving we find
x = 5
click here to see the step by step solution of the equation:
5 + 1 = 6
the two consecutive positive integers are 5 and 6.