Problema Solution
Find the length of a rectangular lot with a perimeter of 72 m if the length is 6 m more than the width.
Answer provided by our tutors
perimeter = 2L + 2w, where 'L' and 'w' are length and width
we have w = L-6
72 = 2*L + 2(L-6)
solving for 'L' we have:
L=21
the length of the lot is 21 meters