Problema Solution
if the sum of six consecutive odd integers is 240, what is the smallest of the five integers?
Answer provided by our tutors
let (2n+1) represent the smallest integer, then the remaining five integers are represented by:
(2n+3), (2n+5), (2n+7), (2n+9) and (2n+11)
240 = (2n+1) + (2n+3) + (2n+5) + (2n+7) + (2n+9) + (2n+11)
solving for n:
n=17
2*17+1 = 35
the smallest integer is 35