Problema Solution
Two cars leave towns
320
kilometers apart at the same time and travel toward each other. One car's rate is
18
kilometers per hour less than the other's. If they meet in
2
hours, what is the rate of the slower car?
Answer provided by our tutors
let
v = the rate of the slower car
v + 18 = the rate of the faster car
d = 320 km the distance between the cars
t = 2 hr the time of the travel
since distance = rate*time we have
vt + (v + 18)t = d
2v + (v + 18)*2 = 320
by solving we find:
v = 71 kph
click here to see the step by step solution of the equation:
the rate of the slower car is 71 kilometers per hour.