Problema Solution
The length of a rectangle is three times its width.
If the area of the rectangle is
300 ft2,find its perimeter.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
A = 300 ft^2 the area of the rectangle
P = 2(l + w) the perimeter of the rectangle
the length of a rectangle is three times its width:
l = 3w
the area of the rectangle A = l*w thus
l*w = 300
plug l = 3w into l*w = 300
3w*w = 300
by solving we find
w = 10 ft
click here to see the step by step solution of the equation:
l = 3*10
l = 30 ft
the perimeter P = 2(l + w)
P = 2(30 + 10)
P = 80 ft
the perimeter of the rectangle is 80 feet.