Problema Solution
The product of two consecutive positive integers is 11 more than their sum. Find the integers.
Answer provided by our tutors
Let the integer are =x and x+1
product=x(x+1)=12
or x^2+x=12
or x^2+x-12=0
or x^2+4x-3x-12=0
or x(x+4)-3(x+4)=0
(x+4)(x-3)=0
so x+4=0 or x-3=0
so x=-4 or x=3
So the integer are 3 and 3+1=4
So the consecutive integer are 3 and 4