Problema Solution

The product of two consecutive positive integers is 11 more than their sum. Find the integers.

Answer provided by our tutors

Let the integer are =x and x+1

product=x(x+1)=12

or x^2+x=12

or x^2+x-12=0

or x^2+4x-3x-12=0

or x(x+4)-3(x+4)=0

(x+4)(x-3)=0

so x+4=0 or x-3=0

so x=-4 or x=3

So the integer are 3 and 3+1=4

So the consecutive integer are 3 and 4