Problema Solution
the perimeter of a rectangular piece of poster board is 96in. the length is 8in. greater than the width. find the width and the length
Answer provided by our tutors
let
w = the width, w>0
l = the length, l>0
P = 96 in the perimeter
the length is 8in. greater than the width:
l = w + 8
the perimeter = 2(l + w) thus:
2(l + w) = 96 divide both sides by 2
l + w = 48
by solving the system of equations:
l = w + 8
l + w = 48
we find:
l = 28 in
w = 20 in
click here to see the step by step solution of the system of equations:
the length is 28 inches.
the width if 20 inches.