Problema Solution
what are the last three digits of 7^5775?
Answer provided by our tutors
7^0 = 01
7^1 = 07
7^2 = 49
7^3 = 343
7^4 = ..401
7^5 = ..807
7^6 = ..649
7^7 = ..543
7^8 = ..801
7^9 = ..607
7^10 = ..249
7^11 = ..743
7^12 = ..201
7^13 = ..407
7^14 = ..849
7^15 = ..943
7^16 = ..601
7^17 = ..207
7^18 = ..449
7^19 = ..143
7^20 = ..001
since 5775 = 20*288 +15 we have
7^5775 = ((7^20)288)*(7^15) has the same last digits as 7^15 that is the last three digits of 7^5775 are 943.