Problema Solution

what are the last three digits of 7^5775?

Answer provided by our tutors

7^0 = 01


7^1 = 07


7^2 = 49


7^3 = 343


7^4 = ..401


7^5 = ..807


7^6 = ..649


7^7 = ..543


7^8 = ..801


7^9 = ..607


7^10 = ..249


7^11 = ..743


7^12 = ..201


7^13 = ..407


7^14 = ..849


7^15 = ..943


7^16 = ..601


7^17 = ..207


7^18 = ..449


7^19 = ..143


7^20 = ..001


since 5775 = 20*288 +15 we have


7^5775 = ((7^20)288)*(7^15) has the same last digits as 7^15 that is the last three digits of 7^5775 are 943.