Problema Solution
Container a and container b have leaks. Container a has 800 ml of water, and is leaking 6 ml per minute. Container b has 1000 ml, and is leaking 10 ml per minute. How many minutes will it take for the two containers to have the same amount of water?
Answer provided by our tutors
let
t = represent the time in minutes after which the containers will have same amount of water
800 - 6t = 1000 - 10t
by solving we find:
t = 50 min
click here to see the step by step solution of the equation:
it will take 50 minutes for the two containers to have same amount of water.