Problema Solution

tracey is fencing in a rectangular garden, using the side of her house as one side of the rectangle. what is the maximum area that she can enclose with 80 ft of fence? what should the dementions of the garden be?

Answer provided by our tutors

let 'x' and 'y' be the dimensions of the rectangle


lets assume that the house is on the side with length equal to y


2x + y = 80


y = 80 - 2x


the area of the rectangle is A = x*y


plug y = 80 - 2x into A = x*y


A = x(80 - 2x)


A = 80x - 2x^2


we need to find the maximum of the parabolic function: A = 80x - 2x^2


since the quotient in front of x^2 is negative (-2 < 0) the function has maximum equal to:


A max = c - b^2/4a, where a = -2, b = 80, c= 0


A max = 0 - 80^2/(4(-2))


A max = 800 ft^2 is the maximum area that she can enclose


by solving 80x - 2x^2 = 800 we find:


x = 20 ft


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y = 80 - 2*20


y = 40 ft


the dimensions of the garden are 20 ft and 40 ft.