Problema Solution

If the length is 3 more than 4 times the width of a rectangle and the perimeter is 76mm, what are the dimensions?

Answer provided by our tutors

let


x = the width


y = the length


P = 76 mm the perimeter


the length is 3 more than 4 times the width of a rectangle:


y = 3 + 4x


the perimeter is 76 mm and we know that the perimeter of rectangle is P = 2(width + length) that is P = 2(x + y)


2(x + y) = 76 divide both sides by 2


x + y = 38


by solving the system of equations:


y = 3 + 4x


x + y = 38


we find:


x = 7 mm


y = 31 mm


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the dimensions of the rectangle are: the width is 7 mm and the length is 31 mm.