Problema Solution
If the length of a rectangle is 3 feet longer than the width and the diagonal is 15 feet, then what are the length and width?
Answer provided by our tutors
x^2 +(x+3)^2= 15^2
x^2+x^2+6x+9=225
2x^2+6x- 216=0
x^2 +3x - 108=0
(x-9)(x+12)=0
x=9
and x=-12 not possible.
width= 9feet
length =12 feet.