Problema Solution
A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(r)=-16r(2)(squared or to the second power)=64, where t is the number of seconds after it is dropped.
a. Find h(1).
b. How long does it take the ball to fall to the earth?
Answer provided by our tutors
h(r)= -16r^2 +64.
a) h(1)= -16(1)^2 +64= -16+64= 48feet
b)h(r)=0
so, -16r^2 +64= 0
r^2= 64/16= 4
r= 2
so, 2secs. is the answer of part b)