Problema Solution

the product of two consecutive integers is 12 less than the square of the lesser integer. find the greater of the two integers

Answer provided by our tutors

the two consecutive integers can be written as:


x and x + 1, where x is integer


x + 1 > x that is x + 1 is the greater integer


the product of two consecutive integers is 12 less than the square of the lesser integer:


x(x + 1) = x^2 - 12


by solving we find:


x = -12


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x + 1 = -12 + 1 = -11


the greater of the two integers is -11.