Problema Solution
There are 3 people and they have 2 drinks and 4 snacks each and wish to trade with each other How many combinations can you have
Answer provided by our tutors
there are total of 2*3 = 6 drinks and 3*4 = 12 snacks.
we need to group them in 2 drinks and 4 snacks thus there are:
we use combinations since the order is not important
C(6, 2)*C(12, 4) = (6!/((2!(6-2)!))(12!/(4!(12 - 4)!)
C(6, 2)*C(12, 4) = 15*495
C(6, 2)*C(12, 4) = 7425
we subtract 1, the start combination and get 7425 - 1 = 7426 possible combinations.