Problema Solution
The perimeter of a rectangle is 40 inches. If the width is 9 inches, what is the area of the rectangle?
Answer provided by our tutors
let
l = the length of the rectangle
w = 9 in the width of the rectangle
P = 40 in is the perimeter
P = 2(l + w)
2(l + w) = P
2(l + 9) = 40
by solving we find:
l = 11 in
click here to see the step by step solution of the equation:
the area of the rectangle A = l*w
A = 9*11
A = 99 in^2
the area of the rectangle is 99 in^2.