Problema Solution
the sum of three consecutive integers is 48 less than twice the smallest of the three integers. Find the integers
Answer provided by our tutors
the three consecutive integers can be written as: x-1, x, x+1 where x is integer
the sum of three consecutive integers is 48 less than twice the smallest of the three integers:
(x - 1) + x + (x + 1) = 2(x - 1) - 48
by solving we find:
x = - 55
click here to see the step by step solution of the equation:
2*(-55) - 1 = -111
2*(-55) = -110
2*(-55) + 1 = -109
the three integers are -111, -110 and -109.