Problema Solution
A baseball league plays 73 games in a season. If the team won 16 more than twice as many games as they lost, how many wins and losses did the team have?
Answer provided by our tutors
let
x = the number of wins
y = the number of losses
A baseball league plays 73 games in a season:
x + y = 73
the team won 16 more than twice as many games as they lost:
x = 16 +2y
by solving the system of equations:
x + y = 73
x = 16 +2y
we find:
x = 54 wins
y = 19 losses
click here to see the step by step solution of the system of equations:
the team had 54 wins and 19 losses.