Problema Solution
Jonathan, a second grader, counted the money in his piggy bank. he had only quarters and dimes. when added up his money, he had 39 coins worth a total of $7.50. how many coins of each kind did he have?
Answer provided by our tutors
1 dime = 10 cents
1 quarter = 25 cents
let
d = the number of dimes, d>0, d is integer
q = the number of quarters, q>0, q is integer
when added up his money, he had 39 coins worth a total of $7.50 = 750 cents
d + q = 39
10d + 25q = 750
by solving the above system of equations we find:
d = 15 dimes
q = 24 quarters
click here to see the step by step solution of the system of equations:
Jonathan has 15 dimes and 24 quarters.