Problema Solution
The perimeter of a standard rectangle is 40 feet. The length is 2 feet longer than the width. Find the dimensions.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
P = 40 ft the perimeter of the rectangle
The length is 2 feet longer than the width:
l = 2 + w
The perimeter P = 2( l + w)
2(l + w) = 40
by solving the system of equations:
l = 2 + w
2(l + w) = 40
we find:
l = 11 ft
w = 9 ft
click here to see the step by step solution of the equation:
the dimensions of the rectangle are 11 ft and 9 ft.