Problema Solution

isaac has 80 pesos in 25 and 10 centavo coins. he has 135 more 10 centavo coins than 25 centavo coins.how many coins of each kind does he have

Answer provided by our tutors

let


x = the number of 10 centavo coins, x>= 0


y = the number of 25 centavo coins, y>= 0


isaac has 80 pesos in 25 and 10 centavo coins:


x + y <= 80


he has 135 more 10 centavo coins than 25 centavo coins:


x = y + 135


by solving the system of equations:


x + y = 80


x = y + 135


x = 107.5


y = - 27.5


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the solutions that we found are not integers.