Problema Solution
isaac has 80 pesos in 25 and 10 centavo coins. he has 135 more 10 centavo coins than 25 centavo coins.how many coins of each kind does he have
Answer provided by our tutors
let
x = the number of 10 centavo coins, x>= 0
y = the number of 25 centavo coins, y>= 0
isaac has 80 pesos in 25 and 10 centavo coins:
x + y <= 80
he has 135 more 10 centavo coins than 25 centavo coins:
x = y + 135
by solving the system of equations:
x + y = 80
x = y + 135
x = 107.5
y = - 27.5
click here to see the step by step solution:
the solutions that we found are not integers.