Problema Solution
PLANE A LEAVES LOS ANGELES FOR NEW YORK AT 500 MPH,AT THE SAME TIME PLANE B LEAVES FROM NEW YORK AT 650 MPH. ASSUME THE DISTANCE FROM LOS ANGELES TO NEW YORK IS 3000 MILES.FIND HOW LONG IT TAKES THEM TO MEET.
Answer provided by our tutors
let
v1 = 500 mph the speed of plane A
v2 = 650 mph the speed of plane B
d = 3,000 mi the distance
t = the time of the flight
since speed = distance/time follows distance = speed*time
we assume the planes are flying towards each-other thus the sum of the distances that each travels is equal to 3,000 mi
v1t + v2t = d
500t + 650t = 3000
by solving we find:
t = 60/23 hr
t = 2 13/23 hr
t = 2 hr 13*60/23 min
t = 2 hr 34 min approximately
click here to see the step by step solution of the equation:
it takes them 2 hr 34 min to meet.