Problema Solution
deoraj bharath wishes to mix coffee worth $6 per lb with coffee worth $3 per lb to get 90lb of mixture worth $4 per lb. How many pounds of the $6 and the $3 coffees will be needed
Answer provided by our tutors
let
x = lbs of the $6 per lb coffee
y = lbs of the $3 per lb coffee
x + y = 90
6x + 3y = 4*90
by solving the above system of equations we find:
x = 30 lbs
y = 60 lbs
click here to see the step by step solution of the system of equations:
30 lbs of the $6 and 60 lbs of the $3 will be needed.