Problema Solution
If a stone is tossed from the top of a 270 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 - 10t + 270, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth's place; include units in answer.
Answer provided by our tutors
When the stone hits the ground h(t)=0.
-9.8t^2-10t+270=0.
9.8t^2+10t-270=0.
Solve the above quadartic equation
t=4.76,-5.78sec.
Ignore negative value.
t=4.76sec.
after 4.7sec the stone hits the ground.