Problema Solution
Joe has a collection of nickles and dimes that is worth $6.10. If the number of dimes was tripled and the number of nickles was decreased by 49, the value of the coins would be $14.05. How many nickles and dimes does he have?
Answer provided by our tutors
Ket n, d be the number of dimes and nikels respectively.
0.05n+0.1d=6.1
Divide through out by 0.05
n+2d=122................1.
3*0.1d+0.05(n-49)=14.05.
0.05n+0.3d=16.5
Divide through out by 0.05
n+6d=330...................2.
Substracting Eqs 1 and 2.
4d=330-122.
d=208/4
=52.
n=122-2d=122-2*52
=18.