Problema Solution
wallace and
vernonville
are 128 miles
apart. a car
leaves
wallace
traveling
towards
vernonville,
and another
car leaves
vernonville at
the same
time, traveling
towards
wallace. the
car leaving
wallace
averages 10
miles per hour
more than the
other, and
they meet
after 1 hour
and 36
minutes. what
are the
average
speeds of the
cars?
Answer provided by our tutors
Let
v = the average speed of the car leaving Vernonville
v + 10 = the average speed of the car leaving Wallace
t = 1 hr 36 min = 1 + 36/60 hr = 1.6 hr the time of the travel
d = 128 mi the distance between Wallace and Vernonville
since average speed = distance/time follows distance = speed*time
vt + (v + 10)t = d
1.6v + 1.6(v + 10) = 128
........
........
v = 35 mph
v + 10 = 35 + 10 = 45 mph
The average speed of the car leaving Vernonville is 35 mph.
The average speed of the car leaving Wallace is 45 mph.