Problema Solution
wallace and vernonville are 128 miles apart. a car leaves wallace traveling towards vernonville, and another car leaves vernonville at the same time, traveling towards wallace. the car leaving wallace averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. what are the average speeds of the cars?
Answer provided by our tutors
Let
v = the average speed of the car leaving Vernonville
v + 10 = the average speed of the car leaving Wallace
t = 1 hr 36 min = 1 + 36/60 hr = 1.6 hr the time of the travel
d = 128 mi the distance between Wallace and Vernonville
since average speed = distance/time follows distance = speed*time
vt + (v + 10)t = d
1.6v + 1.6(v + 10) = 128
........
........
v = 35 mph
v + 10 = 35 + 10 = 45 mph
The average speed of the car leaving Vernonville is 35 mph.
The average speed of the car leaving Wallace is 45 mph.