Problema Solution
A diesel train made a trip to the outer-most station and back. The trip there took 12 hours and the trip back took 15 hours. It averaged 52 mph on the return trip. Find the average speed of the trip there.
Answer provided by our tutors
Let
v1 = the average speed of the trip there
v2 = 52 mph the average speed on the return trip
t1 = 12 hr the time of the trip there
t2 = 15 hr the time of the return trip
Since speed = distance/time follows distance = speed*time:
v1*t1 = v2*t2
12v1 = 52*15
........
........
v1 = 65 mph
The average speed of the trip there is 65 mph.